A man stands one-third of the way between two walls and claps his hands, He hears two distinct echoes 1s apart. If the speed of sound is 330ms-1 the distance between the wall is
Correct Answer: Option E
the man was standing at one third of d(distance between two walls), that means that he is 2/3 d from the other wall, and the echo were distinct echoes (not same reflection)
so since the v is same, make v subject for the two echoes
first echo distance=1/3d, time =x,
for second echo distance=2/3d, time =(x+1)seconds
from eqn v=2d/t
therefore (2(1/3d))/x =(2(2/3d))/x+1
after solving this u would get x =1
then sub 1 for x in the equation v=2d/t to get ur d, so 330=2(1/3d)/1, d =495
but the man stands one third of his distance =⅓d
Making d the subject formula
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His Name is Tiamiyu Abdulbazeet Olawale. He is a student at the University of Ilorin studying Electrical and Electronics Engineering. He likes to give the latest updates about Nigeria and international institutions as he aims at helping people to lay their hands on the right information.