The latent heat of fusion of ice is 80 cal/g. How much heat is required to change 10g of ice at 0°C into water at the same temperature?
A. 80 cal
B. 10 cal
C. 8 cal
D. 800 cal
E. 400 cal
ANSWER: Option D
EXPLANATION: Use the formula Q = mL
Where; Q —> Quantity of heat
m —> mass of the ice
L —> Latent heat of fusion
Just substitute the values for the variable and get your answer!
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