Jamb Physics Past question - Page 11 of 11 - TEEZAB

Jamb Physics Past question

Hello Friend! Are you preparing for the Joint Admissions and Matriculations Board JAMB UTME 2023/2024? If yes, then this is for you! Prepare yourself by treating JAMB Physics Past Questions!

I have prepared a series of JAMB Physics Past Questions from 1988 to 2022 which was prepared with the sole purpose of help you prepare very well for the 2023/2024 JAMB!

This JAMB Physics Past Questions comprise of questions, answers and explanation to the answers. Also, you get to discuss! If you feel one answer is not correct, don’t hesitate to leave a comment.

So, take out your pen and a book and start writing!

 

I must tell that before you start treating past this physics Past Questions, you must have finished reading a physics textbook! At the very least, once!

My friend, here is an opportunity for you to score high in JAMB and to score high, you will need each Mark!

A vapour is said to be saturated when

JAMB 1981 A vapour is said to be saturated when A. more molecules return to the liquid than leave it B. a dynamic equilibrium exists between the liquid molecules and the vapour molecules at a given temperature C. the vapour pressure is atmospheric D. the temperature of the vapour varies E. all molecules are moving …

A vapour is said to be saturated when Read More »

According to Ohm’s law, the ratio V/I is constant for

JAMB 1980 According to Ohm’s law, the ratio V/I is constant for A. an electrolyte B. a diode C. a transistor D. silver E. all of the above Correct Answer: Option D Explanation Metals obey ohms law and silver is a metal. Explain your answer in the comment box below and let’s have a discussion …

According to Ohm’s law, the ratio V/I is constant for Read More »

An object 1cm high placed on the axis 15cm from a converging lens forms an image 30cm from the lens. The size of the image is

Jamb 1978 An object 1cm high placed on the axis 15cm from a converging lens forms an image 30cm from the lens. The size of the image is A. 0.5 cm B. 1.5 cm C. 3 cm D. 2.5 cm E. 2 cm.  ANSWER: Option E EXPLANATION: Using the formula below; Image distance/Object distance = …

An object 1cm high placed on the axis 15cm from a converging lens forms an image 30cm from the lens. The size of the image is Read More »

An air force jet flying with a speed of 335m/s went past an anti-aircraft gun. How far is the aircraft 5s later when the gun was fired

Jamb 1978 An air force jet flying with a speed of 335m/s went past an anti-aircraft gun. How far is the aircraft 5s later when the gun was fired? A. 838 m B. 3350 m  C. 670 m D. 1675 m E. 67 m ANSWER: Option D Explanation: Using the formula Distance = speed × …

An air force jet flying with a speed of 335m/s went past an anti-aircraft gun. How far is the aircraft 5s later when the gun was fired Read More »

An object is positioned between two plane mirrors inclined at right angles to each other. The object is 1 unit distance from each mirror. The number of images formed is

Jamb 1978 An object is positioned between two plane mirrors inclined at right angles to each other. The object is 1 unit distance from each mirror. The number of images formed is A. 1 B. 2 C. 3 D. 4 E. 5 ANSWER: Option C EXPLANATION: Use the equation below to find your answer No. …

An object is positioned between two plane mirrors inclined at right angles to each other. The object is 1 unit distance from each mirror. The number of images formed is Read More »

If NEPA charges 5k per kWh, what is the cost of operating for 24 hours a lamp requiring 1A on a 200V line? 

Jamb 1978 If NEPA charges 5k per kWh, what is the cost of operating for 24 hours a lamp requiring 1A on a 200V line?  A. 24K  B. 55K  C. 40K  D. 26K  E. 32K.  ANSWER: Option A EXPLANATION: refer to the image below!  Previous       Next Or click here to choose!  Of …

If NEPA charges 5k per kWh, what is the cost of operating for 24 hours a lamp requiring 1A on a 200V line?  Read More »

The density of 400cm³ of palm oil was 0.9 g/cm³ before frying. If the density of the oil was 0.6 g/cm³ …..

Jamb 1979 The density of 400cm³ of palm oil was 0.9 g/cm³ before frying. If the density of the oil was 0.6 g/cm³ after frying, assuming no loss of oil due to spilling, its new volume was A. 360cm³ B. 600cm³ C. 240cm³ D. 800cm³ E. 450cm³ ANSWER: Option B EXPLANATION: since Density = mass/volume …

The density of 400cm³ of palm oil was 0.9 g/cm³ before frying. If the density of the oil was 0.6 g/cm³ ….. Read More »